In this short post I will present some curious facts I came across recently.
Given a real number construct the set
, where, as usual,
denotes the floor function. Note that if
is an integer, then
is an (infinite) arithmetic progression starting at
, so we can think of the sets
as generalized arithmetic progressions. In this post I will consider two types of questions about this sets: “can
be disjoint from
?” and “Can the union of finitely many
contain all sufficiently large integer?”.
To try to get some intuition, let’s assume first that is a rational number, say
with
coprime. Then it should be clear that
is a periodic set with period
, because
and since
is integer, taking floors we get
. Thus for any finitely many
with
, if we make
be the least common multiple of
we have that each multiple of
is contained in each
, answering the first question in the negative. Moreover it’s not hard to see that
, so
is not in any of the
and, more generally, no number of the form
is in the union
, answering the second question in the negative.
This gives some intuition about what we could expect for a general (not necessarily rational). Note that if
and
are very close then the sets
and
agree in the beginning, so one can hope to approximate an arbitrary
with rational numbers. After this reasoning the following result should come as a surprise: Continue reading